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lol riiiiigggghhhhttt

rt3(cosx/sinx)+1=1/sinx (rt3cosx+sinx)/sinx=1/sinx rt3cosx+sinx=1 Now we can use the tranformations form, where acosx+bsinx=Rcos(@-alpha) R=rt(a^2+b^2) tan (alpha)=b/a Have a go, if you can't do it then i'll help you out

That's a bit pety, don't you think?

Let all values be in terms of degrees, no denotion tan(105)=tan(45+60) =tan45+tan60/(1-tan45tan60 Now from our exact value triangles tan45=1 and tan60=rt 3 therefore (1+rt3)/(1-rt3) # Im almost 100% sure that would get full marks but just incase i would consider rationalising it...

1) Fuck i hate people that correct spelling in this forum 2) If your going to write a comment on how bad someones spelling is, then you might want to be extra careful writing your own comment

To the current date, i have already earnt $24000 this year ( from Jan 1st 2009), so yes i def qualify, do you think i should lodge an application form now or what until the year is out?

dude, its actually $19503 now for one, also if you earn the $19503 this year, you can still get it for next year ( June 1st 2010)

dude, i was just trying to fit an explanation into one line ok, for christ sake...who cares

Monkey: thats easy you noob, log7 36=x 7^x=36 7^x=7^(ln36/ln7) therefore x=ln36/ln7 or/ 1.841564442 Me: the monkey's pretty amazing Monkey: Got anymore wise guy? Me: Aww now your getting rude

haha... umm yes

ahh yes the old change of base... that old chestnut

haha well it was funny man. Keep up the good work in maths btw. :)

hahaah ah ofcourse

So ive been hearing about the $2000 dollars given to students that will be recieving a independence allowance ( additional $4000 to those who have had to move out of home to attend uni), as of 1st Jan, 2010. Can someone please explain more to me on this, ie. If one had been working this year...

haha sweet... our method is very efficient and a monkey could perform it

i taught myself general maths whilst i was reading your post, its jsut that simple lol

log4 8 = x 4^x=8 (2)^2x=2^3 therefore by equating indices of equal bases x=3/2

thats actually pretty impressive... reps to you! OP: Q1 has already been asked someone in these forums,recently

i) is correct, thats the easy part. ii) basically correct, the number has to follow that : 12( 1/2)^n< 10^-4 and 2^n>120000...do you understand what i mean? Well done nontheless though.

Same here man