2024 HSC Chat (76 Viewers)

WeiWeiMan · Jan 18, 2024

Aeonium said:
just questioning if i can skip the $\frac{du}{dx} = -5 \,\rightarrow\, dx = -\frac{du}5$ and just say $u = 1-5x \,\rightarrow\, dx = -\frac{du}5$ bcz i'm too ceebs to write it all out
$\begin{align*} \int\,&\frac{1}{\left(1-5x\right)^3}\,dx\\ \text{Let } u&=1-5x\\ \frac{du}{dx}&=-5\\ \implies dx&=-\frac{du}{5}\\ \int\,\frac{1}{\left(1-5x\right)^3}\,dx&=-\int\,u^{-3}\,\frac{du}{5}\\ &=-\frac{1}{5}\int u^{-3}\,du\\ &=-\frac{1}{5}\left(\frac{u^{-2}}{2}\right) + C\\ &=-\left(-\frac{u^{-2}}{10}\right)+C\\ &=\frac{1}{10\left(1-5x\right)^2}+C \end{align*}$

na
u could write it like:
x=-u/5
\therefore dx=-du/5

Average Boreduser · Jan 18, 2024

Aeonium said:
just questioning if i can skip the $\frac{du}{dx} = -5 \,\rightarrow\, dx = -\frac{du}5$ and just say $u = 1-5x \,\rightarrow\, dx = -\frac{du}5$ bcz i'm too ceebs to write it all out
$\begin{align*} \int\,&\frac{1}{\left(1-5x\right)^3}\,dx\\ \text{Let } u&=1-5x\\ \frac{du}{dx}&=-5\\ \implies dx&=-\frac{du}{5}\\ \int\,\frac{1}{\left(1-5x\right)^3}\,dx&=-\int\,u^{-3}\,\frac{du}{5}\\ &=-\frac{1}{5}\int u^{-3}\,du\\ &=-\frac{1}{5}\left(\frac{u^{-2}}{2}\right) + C\\ &=-\left(-\frac{u^{-2}}{10}\right)+C\\ &=\frac{1}{10\left(1-5x\right)^2}+C \end{align*}$

alternatively u can skip like 8 of those lines if u consider 1-5x as x

WeiWeiMan · Jan 18, 2024

Aeonium said:
just questioning if i can skip the $\frac{du}{dx} = -5 \,\rightarrow\, dx = -\frac{du}5$ and just say $u = 1-5x \,\rightarrow\, dx = -\frac{du}5$ bcz i'm too ceebs to write it all out
$\begin{align*} \int\,&\frac{1}{\left(1-5x\right)^3}\,dx\\ \text{Let } u&=1-5x\\ \frac{du}{dx}&=-5\\ \implies dx&=-\frac{du}{5}\\ \int\,\frac{1}{\left(1-5x\right)^3}\,dx&=-\int\,u^{-3}\,\frac{du}{5}\\ &=-\frac{1}{5}\int u^{-3}\,du\\ &=-\frac{1}{5}\left(\frac{u^{-2}}{2}\right) + C\\ &=-\left(-\frac{u^{-2}}{10}\right)+C\\ &=\frac{1}{10\left(1-5x\right)^2}+C \end{align*}$

as average boreduser said (kinda), your working is hella unnecessary
u can rewrite it as like

$\begin{align*} \int \frac{1}{(1-5x)^3} \text dx &=\int (1-5x)^{-3} \text dx \\ &= \(1-5x)^{-2} \cdot \frac{1}{-2} \cdot \frac{1}{-5} + C \\ &= \frac{1}{10(1-5x)^2} + C \end{align*}$

Average Boreduser said:
alternatively u can skip like 8 of those lines if u consider 1-5x as x

Aeonium · Jan 18, 2024

Average Boreduser said:
alternatively u can skip like 8 of those lines if u consider 1-5x as x

as u you mean ?

Aeonium · Jan 18, 2024

WeiWeiMan said:
as average boreduser said (kinda), your working is hella unnecessary
u can rewrite it as like

$\begin{align} \int \frac{1}{(1-5x)^3} \ text dx &=\int (1-5x)^{-3} \text dx \\ &= \(1-5x)^{-2} \cdot \frac{1}{-2} \cdot \frac{1}{-5} + C \\ &= \frac{1}{10(1-5x)^2} + C \end{align}$

uh the qn asked for substitution (sorry should've clarified)

Average Boreduser · Jan 18, 2024

Aeonium said:
uh the qn asked for substitution (sorry should've clarified)

oh fair enough then

mb

Aeonium · Jan 18, 2024

Average Boreduser said:
oh fair enough then mb

naw it's my bad i should've clarified in the start

Cute-Duckie · Jan 18, 2024

Aeonium said:
currently
View attachment 42158 View attachment 42159
the plan is to import the average mark from each individual sheet to the 'Analytics' sheet –> colour indicator if your average is meeting your goals or not as well as the other pages but this requires making custom scripts
this is most definitely not a good use of my time but it's fine it's motivation woops the reds are mismatched i hate selecting in colour palettes

woah this is so cool can you make like a blank copy and share it with eveyrone when you're done?? this seems super useful

Aeonium · Jan 19, 2024

Cute-Duckie said:
woah this is so cool can you make like a blank copy and share it with eveyrone when you're done?? this seems super useful

i think i'm pretty far from finishing it tho but i probably will

Cathode_RT · Jan 19, 2024

damn the 2023 stuff got archived

good luck you 2024 youngins

WeiWeiMan · Jan 19, 2024

Cathode_RT said:
damn the 2023 stuff got archived
View attachment 42186

good luck you 2024 youngins

yooooo cathode rt

Cathode_RT · Jan 19, 2024

WeiWeiMan said:
yooooo cathode rt

wassup

yolo tengo · Jan 19, 2024

WeiWeiMan said:
as average boreduser said (kinda), your working is hella unnecessary

nah it depends tho, like sum teachers get on your skin bc of 'not showing enough working' (my teacher) so some ppl have to do all the unnecessary working out

WeiWeiMan · Jan 19, 2024

yolo tengo said:
nah it depends tho, like sum teachers get on your skin bc of 'not showing enough working' (my teacher) so some ppl have to do all the unnecessary working out

unless the question states otherwise, the reverse chain rule is very much an accepted method
reverse chain rule is literally on the formula sheet as an integration method

Aeonium · Jan 19, 2024

Aeonium said:
i think i'm pretty far from finishing it tho but i probably will

upcoming/trying to do:
- colour matching tab/theme
- atar contrib thing (maybe, depends on how hard it is)
- number completed/completion rate 2
- mistake analytics (e.g silly, algebra, did not know how the fuck to approach, calculation/rounding) per subject (will show number of mistakes categorized by aforementioned types or more
- currently you have to retype the function/refresh page for it to update – might try to fix
- might turn into something like this:

but i'm kinda ceebs tbh
(should be able to put in unlimited subject based off how i made it)

edit: if i turn it into a menu it needs access to stuff and i dont feel comfortable with that

its_ace21 · Jan 19, 2024

@Aeonium if u dont get 99.95 im gonna sue

Aeonium · Jan 19, 2024

its_ace21 said:
@Aeonium if u dont get 99.95 im gonna sue

i'm not getting 99.95 i don't try hard enough lol (and i don't need it)

xoNat · Jan 19, 2024

Aeonium said:
i'm not getting 99.95 i don't try hard enough lol (and i don't need it)

What do u wanna do again

Aeonium · Jan 19, 2024

Aeonium said:
i'm not getting 99.95 i don't try hard enough lol (and i don't need it)

if i did i would call bs; would actually be annoyed because i feel like a lot of people put in way more effort than me for like 1/2 of the results

i don't think i'd deserve anything above like 99.1 (even that's a stretch)

Aeonium · Jan 19, 2024

xoNat said:
What do u wanna do again

surgery at tafe

2024 HSC Chat (76 Viewers)

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