Class of 2025 (2025 HSC CHAT) (31 Viewers)

quokka

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I believe there's an inverse relationship between time 'til trials and frequency of messages in this thread :hat:

Who's doing the experimental write-up?
what did u just say im dyslexic
 

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I believe there's an inverse relationship between time 'til trials and frequency of messages in this thread :hat:

Who's doing the experimental write-up?
The days till trials is inversely proportional to the number of messages on this chat If it trials are in 1 day and there are 200 messages today, how many messages would there be if trials were in half a day? (idk if this is correct but I tried so hard)
 

quokka

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The days till trials is inversely proportional to the number of messages on this chat If it trials are in 1 day and there are 200 messages today, how many messages would there be if trials were in half a day? (idk if this is correct but I tried so hard)
what would you do if when you okay said he said yes would go
 

reniiiblaseee

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yeah same but my cousin helps me with eng cuz hes supa smart just start by taking the first sentence of ur intro and adapt it to the question. adapting is literally changing up like 3 words in ur first sentence then voila itll flow
scaffolding🀟🀟🀟
 

Hehehe22

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The days till trials is inversely proportional to the number of messages on this chat If it trials are in 1 day and there are 200 messages today, how many messages would there be if trials were in half a day? (idk if this is correct but I tried so hard)
Let k be the constant of proportionality, m be the number of messages and t be the time until trials.

Therefore, m = k/t

Sub m=200, t=1

200 = k/1

k=200

Thus, m=200/t

When t = 0.5,

m=200/0.5

Thus, m=400, i.e. there will be 400 messages if trials were in half a day.

(I actually don't know if this is correct)
 

Study to success

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Let k be the constant of proportionality, m be the number of messages and t be the time until trials.

Therefore, m = k/t

Sub m=200, t=1

200 = k/1

k=200

Thus, m=200/t

When t = 0.5,

m=200/0.5

Thus, m=400, i.e. there will be 400 messages if trials were in half a day.

(I actually don't know if this is correct)
see guys I'm helping u guys study for ur math trials lmao
 

reniiiblaseee

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Let k be the constant of proportionality, m be the number of messages and t be the time until trials.

Therefore, m = k/t

Sub m=200, t=1

200 = k/1

k=200

Thus, m=200/t

When t = 0.5,

m=200/0.5

Thus, m=400, i.e. there will be 400 messages if trials were in half a day.

(I actually don't know if this is correct)
okayyyy getting that math state rank
 

quokka

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Let k be the constant of proportionality, m be the number of messages and t be the time until trials.

Therefore, m = k/t

Sub m=200, t=1

200 = k/1

k=200

Thus, m=200/t

When t = 0.5,

m=200/0.5

Thus, m=400, i.e. there will be 400 messages if trials were in half a day.

(I actually don't know if this is correct)
i actually didnt even know that was a math question thats how u know i got an E in year10 math
 

Study to success

Leader of the Anti HSC English Party
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