Re: HSC Physics Marathon 2014
Assuming length of second wire = length of first wire,
F = 0.05N (force exerted on first wire perpendicularly towards balance)
Now, old weight w1 = mg = (8.154)x 9.8 --- assuming g = 9.8
Therefore new weight w2 = w1 + 0.05N
Thus, new reading = w2/9.8 ~~ 8.159 g...